A small block of mass 100g is tied to a spring of spring constant 7 . 5N m ^ - 1 and length 20cm . The other end of spring is fixed at a particular point A . If the block moves in a circular path on a smooth horizontal

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Correct answer: A. 0 . 75N

Centripetal force will be provided by the spring force. Let the elongation in the spring be $x$ , then we can write
$⇒ kx = m{\omega}^{2} ( r + x )$
$⇒ 7 . 5x = 2 . 5 ( 0 . 2 + x )$
$⇒ x = \dfrac{0 . 5}{5} = 0 . 1$
Therefore, required tension will be $T = kx = 0 . 75N$ .

A small block of mass 100g is tied to a spring of spring constant 7...

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