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JEE Main20236 Apr 2023Morning ShiftPhysicsLaws of MotionActual

A small block of mass 100 g is tied to a spring of spring constant 7 . 5 N m - 1 and length 20 cm . The other end of spring is fixed at a particular point A . If the block moves in a circular path on a smooth horizontal surface with constant angular velocity 5 rad s - 1 about point A , then tension in the spring is

Options

  1. A0 . 75   N
  2. B0 . 25   N
  3. C0 . 50   N
  4. D1 . 5   N

Correct answer

A. 0 . 75   N

Step-by-step solution

Centripetal force will be provided by the spring force. Let the elongation in the spring be x , then we can write ⇒ k x = m ω 2 ( r + x ) ⇒ 7 . 5   x = 2 . 5 ( 0 . 2 + x ) ⇒ x = 0 . 5 5 = 0 . 1 Therefore, required tension will be T = k x = 0 . 75   N .

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