A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below. The coefficient of kinetic friction between the surface and block is 0 . 02 . The acceleration of block is: (Given g = 10 m s - 2 .)

Step-by-step solution

For hanging block, 40 - T = 4 a           ⋯ 1 Now, maximum value of friction force will be, f m a x = μ N = 0 . 02 × 40 × 10 = 8   N For block on table, T - 8 = 40 a           ⋯ 2 From equation(1) and equation (2), we get 32 = 44 a   ⇒ a = 32 44 = 8 11   m   s - 2