A block of mass M placed inside a box descends vertically with acceleration a . The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of ' a ' will be

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Correct answer: B. (3g)/(4)

The forces acting on the block are shown below.

Here, $N$ is normal force and box is falling with acceleration $a$ .

A block of mass M placed inside a box descends vertically with acceleration a . The block exerts a force equal to

From figure, $Mg - N = Ma$

According to question, $N = \dfrac{Mg}{4}$

$\dfrac{Mg}{4} = M\left(g - a\right)$

$⇒ a = \dfrac{3g}{4}$

A block of mass M placed inside a box descends vertically with...

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