A block of metal weighing 2kg is resting on a frictionless plane...

A block of metal weighing $2kg$ is resting on a frictionless plane (as shown in figure). It is struck by a jet releasing water at a rate of $1kg{s}^{- 1}$ and at a speed of $10{ms}^{- 1}$ . Then, the initial acceleration of the block, in $m{s}^{- 2}$ , will be

A block of metal weighing 2kg is resting on a frictionless plane (as shown in figure). It is struck by a jet releasing

Options

A $3$
B $6$
C $5$
D $4$

Correct answer

C. $5$

Step-by-step solution

Let velocity of water jet be $v$ .

So, force applied is $F = \dfrac{\Deltap}{\Deltat} = \dfrac{\left(∆ mv\right)}{\Deltat}$

$⇒ ma = \dfrac{\left(∆ mv\right)}{\Deltat}$

Acceleration of block, $a = \dfrac{1 \times 10}{2}$

$a = 5m{s}^{- 2}$

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