JEE Main202227 Jun 2022Evening ShiftPhysicsLaws of MotionActual
A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is α = tan - 1 x × 10 - 1 . The value of x is _____ . (Given, g = 10 m s - 2 )
Correct answer
0
Step-by-step solution
⇒ T sin θ = 100 and T cos θ = 30 Therefore, tan θ = 10 3 Then, tan α = 3   10 ⇒ α = tan - 1 3 × 10 - 1 Hence, value of x = 3 .