JEE Main 202227 JuneMorning Shift
- Exam
- JEE Main
- Year
- 2022
- Date
- 27 June
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Laws of Motion
JEE Main 2022 · 27 June · Morning Shift · Physics · Laws of Motion
A system of two blocks of masses m = 2kg and M = 8kg is placed on a...
A system of two blocks of masses is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is . The maximum horizontal force that can be applied to the block of mass so that the blocks move together will be \left(g = 9 . 8m{s}^{- 2}\right)$
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Maximum acceleration of the upper block will be,
{a}_\max = \mug = 0 . 5 \times 9 . 8 = 4 . 9m{s}^{- 2}
Therefore, maximum force that can be applied on the lower block is,
{F}_\max = \left(2 + 8\right) \times 4 . 9 = 49N