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JEE Main202227 Jun 2022Morning ShiftPhysicsLaws of MotionActual

A system of two blocks of masses m = 2 kg and M = 8 kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0 . 5 . The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be g = 9 . 8 m s - 2

Options

  1. A9 . 8   N
  2. B39 . 2   N
  3. C49   N
  4. D78 . 4   N

Correct answer

C. 49   N

Step-by-step solution

Maximum acceleration of the upper block will be, a m a x = μ g = 0 . 5 × 9 . 8 = 4 . 9   m   s - 2 Therefore, maximum force that can be applied on the lower block is, F max = 2 + 8 × 4 . 9 = 49   N

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