A block of mass m slides on the wooden wedge, which in turn slides...

Ncos60 ° = M{a}_{1} = 16{a}_{1}$<br />$⇒ N = 32{a}_{1}$<br />$⊥$to incline</p><p>$N = 8gcos30 ° - 8{a}_{1}\sin 30 ° ⇒ 32{a}_{1} = 44\sqrt{3}g - 4{a}_{1}$</p><p>$⇒ {a}_{2} = \dfrac{\sqrt{3}}{9}g$</p><p>Along incline</p><p>$8gsin30 ° + 8{a}_{1}\cos 30 ° = m{a}_{2} = 8{a}_{2}$</p><p>${a}_{2} = g \times \dfrac{1}{2} + \dfrac{\sqrt{3}}{9}g \cdot \dfrac{\sqrt{3}}{2} = \dfrac{2g}{3}