A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg , M = 16 kg Assume all the surfaces shown in the figure to be frictionless.

Step-by-step solution

N cos 60 ° = M a 1 = 16 a 1 ⇒ N = 32 a 1 ⊥ to incline N = 8 gcos 30 ° - 8 a 1 sin 30 ° ⇒ 32 a 1 = 44 3 g - 4 a 1 ⇒    a 2 = 3 9 g Along incline 8 gsin 30 ° + 8 a 1 cos 30 ° = m a 2 = 8 a 2 a 2 = g × 1 2 + 3 9 g · 3 2 = 2 g 3