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JEE Main 20211 SeptemberEvening Shift
Exam
JEE Main
Year
2021
Date
1 September
Shift
Evening Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2021 · 1 September · Evening Shift · Physics · Laws of Motion

The average translational kinetic energy of N _ 2 gas molecules at...

The average translational kinetic energy of N2{N}_{2} gas molecules at _________ C ∘ becomes equal to the K.E.K . E . of an electron accelerated from rest through a potential difference of 0.1volt.</p><p>(GivenkB=1.38×10−23JK−1)(Fillthenearestinteger).</p>0 . 1volt .</p><p>(Given {k}_{B} = 1 . 38 \times {10}^{- 23}J{K}^{- 1}) (Fill the nearest integer).</p>

Correct answer

0

Step-by-step solution

Given

Translation K.E.K . E . of N2=K.E{N}_{2} = K . E of electron

32kT=eV\dfrac{3}{2}kT = eV

32×1.38×10−23T=1.6×10−19×0.1⇒T=773K\dfrac{3}{2} \times 1 . 38 \times {10}^{- 23}T = 1 . 6 \times {10}^{- 19} \times 0 . 1 ⇒ T = 773K

T=773−273=500°CT = 773 - 273 = 500 ° C

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