JEE Main 202117 MarchEvening Shift
- Exam
- JEE Main
- Year
- 2021
- Date
- 17 March
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Laws of Motion
JEE Main 2021 · 17 March · Evening Shift · Physics · Laws of Motion
A body of mass 1kg rests on a horizontal floor with which it has a...
A body of mass rests on a horizontal floor with which it has a coefficient of static friction . It is desired to make the body move by applying the minimum possible force . The value of will be _______.(Round off to the Nearest Integer) [Take ]
Correct answer
0
Step-by-step solution
Fcos\theta = \muN⇒ Fsin\theta + N = mg⇒ F = \dfrac{\mumg}{cos\theta + \mu sin\theta}{F}_\min = \dfrac{\mumg}{\sqrt{1 + {\mu}^{2}}} = \dfrac{\dfrac{1}{\sqrt{3}} \times 10}{\dfrac{2}{\sqrt{3}}} = 5