JEE Main202117 Mar 2021Evening ShiftPhysicsLaws of MotionActual
A boy of mass 4 kg is standing on a piece of wood having mass 5 kg . If the coefficient of friction between the wood and the floor is 0 . 5 , the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is _______ N . (Round off to the Nearest Integer) [Take g = 10 m s - 2
Correct answer
0
Step-by-step solution
N + T = 90 T = μ N = 0 . 5 ( 90 - T ) 1 . 5 T = 45 T = 30   N