Two blocks ( m = 0 . 5kg and M = 4 . 5kg ) are arranged on a...

Two blocks ( $m = 0 . 5kg$ and $M = 4 . 5kg$ ) are arranged on a horizontal frictionless table as shown in the figure. The coefficient of static friction between the two blocks is $\dfrac{3}{7} .$ Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is $N .$ (Round off to the Nearest Integer) [Take $g$ as $9 . 8m{s}^{- 2}$ ]

Two blocks ( m = 0 . 5kg and M = 4 . 5kg ) are arranged on a horizontal frictionless table as shown in the figure. The

Correct answer

Step-by-step solution

${a}_\max = \mug = \dfrac{3}{7} \times 9 . 8$

$F = ( M + m ) {a}_\max = 5{a}_\max$

$= 21N$

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