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JEE Main202117 Mar 2021Morning ShiftPhysicsLaws of MotionActual

Two blocks ( m = 0 . 5   kg and M = 4 . 5   kg ) are arranged on a horizontal frictionless table as shown in the figure. The coefficient of static friction between the two blocks is 3 7 . Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is N . (Round off to the Nearest Integer) [Take g as 9 . 8   m   s - 2 ]

Correct answer

0

Step-by-step solution

a max = μ g = 3 7 × 9 . 8 F = ( M + m ) a max = 5 a max = 21   N

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