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JEE Main 202126 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Morning Shift
Subject
Physics
Chapter
Laws of Motion

JEE Main 2021 · 26 February · Morning Shift · Physics · Laws of Motion

A particle is moving with uniform speed along the circumference of...

A particle is moving with uniform speed along the circumference of a circle of radius RR under the action of a central fictitious force FF which is inversely proportional to R3{R}^{3}. Its time period of revolution will be given by :

Options

  1. AT∝R43T ∝ R\dfrac{4}{3}
  2. BT∝R52T ∝ R\dfrac{5}{2}
  3. CT∝R32T ∝ R\dfrac{3}{2}
  4. DT∝R2T ∝ {R}^{2}

Correct answer

D. T∝R2T ∝ {R}^{2}

Step-by-step solution

F∝1R3F ∝ \dfrac{1}{{R}^{3}}

KR3=mω2R\dfrac{K}{{R}^{3}} = m{\omega}^{2}R

ω2=Km×1R4{\omega}^{2} = \dfrac{K}{m} \times \dfrac{1}{{R}^{4}}

(2πT)2=Km×1R4{\left(\dfrac{2\pi}{T}\right)}^{2} = \dfrac{K}{m} \times \dfrac{1}{{R}^{4}}

T2∝R4{T}^{2} ∝ {R}^{4}

T∝R2T ∝ {R}^{2}

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