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JEE Main202126 Feb 2021Morning ShiftPhysicsLaws of MotionActual

A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to R 3 . Its time period of revolution will be given by :

Options

  1. AT ∝ R 4 3
  2. BT ∝ R 5 2
  3. CT ∝ R 3 2
  4. DT ∝ R 2

Correct answer

D. T ∝ R 2

Step-by-step solution

F ∝ 1 R 3 K R 3 = m ω 2 R ω 2 = K m × 1 R 4 2 π T 2 = K m × 1 R 4 T 2 ∝ R 4 T ∝ R 2

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