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JEE Main202126 Feb 2021Morning ShiftPhysicsLaws of MotionActual

As shown in the figure, a block of mass 3 kg is kept on a horizontal rough surface of coefficient of friction 1 3 3 . The critical force to be applied on the vertical surface as shown at an angle 60 ° with horizontal such that it does not move, will be 3 x . The value of x will g = 10 m s - 2 ; sin 60 ° = 3 2 ; cos 60 ° = 1 2

Correct answer

0

Step-by-step solution

F cos 60 ° = μ N or F 2 = 1 3 3   N                   … 1 & N = sin 60 ° + 3 g    … 2 From equation 1 & 2 F 2 = 1 3 3 F 3 2 + 3 g ⇒ F = g = 10 Newton = 3 x So x = 10 3 = 3 . 33

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