Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force $F$ at a point $b$ above its centre of mass (see figure). If the coefficient of friction is $\mu = 0.4$ , the maximum possible value of $100 \times \dfrac{b}{a}$ for a box not to topple before moving is ________

Question

Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force

F

at a point

b

above its centre of mass (see figure). If the coefficient of friction is

\mu = 0.4

, the maximum possible value of

100 \times \dfrac{b}{a}

for a box not to topple before moving is ________

Quantrex Academy · Accepted Answer

Correct answer: 0

For no toppling F((a)/(2) + b) ≤ mg(a)/(2) μ(a)/(2) + ≤ (a)/(2) 0 . 2a + 0.4b ≤ 0.5a 0.4b ≤ 0.3a b ≤ (3a)/(2) b ≤ 0.75a (in limiting case) But it is not possible as b can maximum be equal to 0 . 5a ∴ (100(b)/(a)) _ = 50.00

Consider a uniform cubical box of side a on a rough floor that is...

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