JEE Main20199 Jan 2019Evening ShiftPhysicsLaws of MotionActual
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 ° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is g = 10 m s - 2
Options
- A100 N
- B200 N
- C140 N
- D70 N
Correct answer
A. 100 N
Step-by-step solution
T cos ⁡ 45 ° = m g T sin ⁡ 45 ° = F t a n   45 ° = F m g F = m g = 100   N