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JEE Main20199 Jan 2019Morning ShiftPhysicsLaws of MotionActual

A block of mass 10 k g is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6 . What should be the minimum value of force P , such that the block does not move downward? (take g = 10 m s - 2 )

Options

  1. A23 N
  2. B25 N
  3. C18 N
  4. D32 N

Correct answer

D. 32 N

Step-by-step solution

Block will be at rest m g sin ⁡ θ + 3 N = P + f 10 × 10 × 1 2 + 3 = P + μ m g cos ⁡ θ ( ∵ To get P minimum friction must be minimum) P m i n = 50 2 + 3 - 0.6 × 10 × 10 × 1 2 = 20 2 + 3 = 32 N

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