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JEE Main 201322 AprilOnline
Exam
JEE Main
Year
2013
Date
22 April
Mode
Online
Subject
Physics
Chapter
Laws of Motion

JEE Main 2013 · 22 April · Online · Physics · Laws of Motion

A body starts from rest on a long inclined plane of slope 45^ . The...

A body starts from rest on a long inclined plane of slope 45∘45^{\circ}. The coefficient of friction between the body and the plane varies as μ=0.3x\mu=0.3 x, where xx is distance travelled down the plane. The body will have maximum speed (for g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2 ) when x=x=

Options

  1. A9.8 m9.8 \mathrm{~m}
  2. B27 m27 \mathrm{~m}
  3. C12 m12 \mathrm{~m}
  4. D3.33 m3.33 \mathrm{~m}

Correct answer

D. 3.33 m3.33 \mathrm{~m}

Step-by-step solution

When the body has maximum speed then μ=0.3x=tan⁡45∘∴x=3.33 m\begin{aligned}& \mu=0.3 \mathrm{x}=\tan45^{{}^{\circ}} \\ & \therefore \mathrm{x}=3.33 \mathrm{~m} \end{aligned}
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