A block is kept on a frictionless inclined surface with angle of...

A block is kept on a frictionless inclined surface with angle of inclination

\alpha

. The incline is given an acceleration a to keep the block stationary. Then a is equal to A block is kept on a frictionless inclined surface with angle of inclination α . The incline is given an acceleration a

A block is kept on a frictionless inclined surface with angle of inclination α . The incline is given an acceleration a

Options

A $\mathrm{g} / \tan \alpha$
B $\mathrm{g} \operatorname{cosec} \alpha$
Cg
D $\mathrm{g} \operatorname\tan \alpha$

Correct answer

D. $\mathrm{g} \operatorname\tan \alpha$

Step-by-step solution

m g \sin \alpha=m a \cos \alpha

\therefore

\mathrm{a}=\mathrm{g}

\tan \alpha

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