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JEE Main 2005

Exam: JEE Main
Year: 2005
Subject: Physics
Chapter: Laws of Motion

JEE Main 2005 · Physics · Laws of Motion

A particle of mass 0.3 ~kg is subjected to a force F=-k x with k=15...

A particle of mass

0.3 \mathrm{~kg}

is subjected to a force

F=-k x

with

k=15 \mathrm{~N} / \mathrm{m}

. What will be its initial acceleration if it is released from a point

20 \mathrm{~cm}

away from the origin?

Options

A $3 \mathrm{~m} / \mathrm{s}^2$
B $15 \mathrm{~m} / \mathrm{s}^2$
C $5 \mathrm{~m} / \mathrm{s}^2$
D $10 \mathrm{~m} / \mathrm{s}^2$

Correct answer

D. $10 \mathrm{~m} / \mathrm{s}^2$

Step-by-step solution

a=\frac{k x}{m}=10 \mathrm{~m} / \mathrm{s}^2

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