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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2026 · 21 January · Morning Shift · Physics · Magnetic Effects of Current

A current carrying solenoid is placed vertically and a particle of...

A current carrying solenoid is placed vertically and a particle of mass mm with charge QQ is released from rest. The particle moves along the axis of solenoid. If gg is acceleration due to gravity then the acceleration (a) of the charged particle will satisfy :

Options

  1. Aa>ga>g
  2. B0<a<g0 < a < g
  3. Ca=0a=0
  4. Da=ga=g

Correct answer

D. a=ga=g

Step-by-step solution

Inside a solenoid, magnetic field B⃗\vec{B} is uniform and parallel to the axis.
Particle moves along the axis, so velocity v⃗\vec{v} is parallel to B⃗\vec{B}.
Magnetic force F⃗=Q(v⃗×B⃗)=0\vec{F} = Q(\vec{v} \times \vec{B}) = 0 (since v⃗∥B⃗\vec{v} \parallel \vec{B})
Only gravity acts on the particle.
Acceleration a=ga = g
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