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JEE Main20254 Apr 2025Evening ShiftPhysicsMagnetic Effects of CurrentActual

A particle of charge 1.6 C and mass 16 ~g is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to magnetic field. The time required for the particle to return to original location for the first time is ________ S. ( =3.14)

Correct answer

0

Step-by-step solution

Angle between V of charge & ~B is 90^ motion will be uniform circular motion time period is given by T = 2 ~m qB = 2 16 10⁻⁹ ~kg 1.6 10⁻⁶ 6.28 T =0.01 seconds NTA Answer is 10 Correct Answer is 0 (nearest integer)

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