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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2025 · 4 April · Evening Shift · Physics · Magnetic Effects of Current

A particle of charge 1.6 μ C and mass 16 μ ~g is present in a...

A particle of charge 1.6μC1.6 \mu \mathrm{C} and mass 16μ g16 \mu \mathrm{~g} is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to magnetic field. The time required for the particle to return to original location for the first time is ________ S. (π=3.14)(\pi=3.14)A particle of charge 1.6 μ C and mass 16 μ ~g is present in a strong magnetic field of 6.28 T. The particle is then

Correct answer

0

Step-by-step solution

A particle of charge 1.6 μ C and mass 16 μ ~g is present in a strong magnetic field of 6.28 T. The particle is then
Angle between V→\overrightarrow{\mathrm{V}} of charge & B→\& \overrightarrow{\mathrm{~B}} is 90∘90^{\circ} motion will be uniform circular motion time period is given by
T=2π mqB=2π×16×10−9 kg1.6×10−6×6.28\mathrm{T}=\frac{2 \pi \mathrm{~m}}{\mathrm{qB}}=\frac{2 \pi \times 16 \times 10^{-9} \mathrm{~kg}}{1.6 \times 10^{-6} \times 6.28}
T=0.01\mathrm{T}=0.01 seconds
NTA Answer is 10
Correct Answer is 0 (nearest integer)
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