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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2025 · 28 January · Evening Shift · Physics · Magnetic Effects of Current

An infinite wire has a circular bend of radius a, and carrying a...

An infinite wire has a circular bend of radius a, and carrying a current I as shown in figure. The magnitude of
An infinite wire has a circular bend of radius a, and carrying a current I as shown in figure. The magnitude of magnetic field at the origin OO of the arc is given by :

Options

  1. Aμ04πIa[π2+1]\frac{\mu_0}{4 \pi} \frac{I}{a}\left[\frac{\pi}{2}+1\right]
  2. B\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+2\right]
  3. C\frac{\mu_0}{2 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{\pi}{2}+2\right]
  4. D\frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+1\right]

Correct answer

D. \frac{\mu_0}{4 \pi} \frac{\mathrm{I}}{\mathrm{a}}\left[\frac{3 \pi}{2}+1\right]

Step-by-step solution

An infinite wire has a circular bend of radius a, and carrying a current I as shown in figure. The magnitude of
B1=μ0i4πa⊗B2=μ04πia(3π2)⊗B3=0 B=μ04πia(13π2)⊗\begin{aligned} & \mathrm{B}_1=\frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{a}} \otimes \\ & \mathrm{B}_2=\frac{\mu_0}{4 \pi} \frac{\mathrm{i}}{\mathrm{a}}\left(\frac{3 \pi}{2}\right) \otimes \\ & \mathrm{B}_3=0 \\ & \mathrm{~B}=\frac{\mu_0}{4 \pi} \frac{\mathrm{i}}{\mathrm{a}}\left(1 \frac{3 \pi}{2}\right) \otimes\end{aligned}
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