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A proton and a deutron ( q=+ e , m=2.0 u ) having same kinetic energies enter a region of uniform magnetic field B , moving perpendicular to B . The ratio of the radius r_d of deutron path to the radius r_p of the proton path is:

Options

  1. A2 : 1
  2. B1: 1
  3. C1: 2
  4. D1: 2

Correct answer

A. 2 : 1

Step-by-step solution

In uniform magnetic field, R = m qB = 2 ~m ( ~K . E ) qB Since same K.E aligned & R m q & R _ deutron R _ proton = m _ d m _ p q _ p q _ d & = 2 1 & _ d : _ p = 2 : 1 aligned

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