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JEE Main 20249 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
9 April
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2024 · 9 April · Morning Shift · Physics · Magnetic Effects of Current

A square loop of edge length 2 ~m carrying current of 2 ~A is...

A square loop of edge length 2 m2 \mathrm{~m} carrying current of 2 A2 \mathrm{~A} is placed with its edges parallel to the xx yy axis. A magnetic field is passing through the x−yx-y plane and expressed as B⃗=B0(1+4x)k^\vec{B}=B_0(1+4 x) \hat{k}, where B0=5 TB_0=5 \mathrm{~T}. The net magnetic force experienced by the loop is _______ N\mathrm{N}.

Correct answer

0

Step-by-step solution

B(x=0)=B0,B(x=2)=9B0 Also, F=iℓB⇒F1=iℓB0F2=9iℓB0F=F2−F1=8iℓB0=8×2×2×5F=160N\begin{aligned} & \mathrm{B}(\mathrm{x}=0)=\mathrm{B}_0, \quad \mathrm{ B}(\mathrm{x}=2)=9 \mathrm{ B}_0 \\ & \text{ Also, } \mathrm{F}=\mathrm{i} \ell \mathrm{B} \\ & \Rightarrow \mathrm{F}_1=\mathrm{i} \ell \mathrm{B}_0 \quad & \quad \mathrm{ F}_2=9 \mathrm{i} \ell \mathrm{B}_0 \\ & \mathrm{ F}=\mathrm{F}_2-\mathrm{F}_1=8 \mathrm{i} \ell \mathrm{B}_0=8 \times 2 \times 2 \times 5 \\ & \mathrm{ F}=160 \mathrm{ N}\end{aligned}
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