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JEE Main 202431 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2024 · 31 January · Evening Shift · Physics · Magnetic Effects of Current

A uniform magnetic field of 2 × 10 ^ - 3 T acts along positive...

A uniform magnetic field of 2×10−3T2 \times {10}^{- 3}T acts along positive Y-direction. A rectangular loop of sides 20cm20cm  and 10cm10cm with current of 5A5A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is :A uniform magnetic field of 2 × 10 ^ - 3 T acts along positive Y-direction. A rectangular loop of sides 20cm and 10cm

Options

  1. A2×10−4Nm2 \times {10}^{- 4}Nm along positive Z –direction
  2. B2×10−4Nm2 \times {10}^{- 4}Nm along negative Z-direction
  3. C2×10−4Nm2 \times {10}^{- 4}Nm along positive X-direction
  4. D2×10−4Nm2 \times {10}^{- 4}Nm along positive Y-direction

Correct answer

B. 2×10−4Nm2 \times {10}^{- 4}Nm along negative Z-direction

Step-by-step solution

A uniform magnetic field of 2 × 10 ^ - 3 T acts along positive Y-direction. A rectangular loop of sides 20cm and 10cm

Magnetic moment is given by, M→=iA→\overset{\to}{M} = i\overset{\to}{A}

= 5 \times \left(0 . 2\right) \times \left(0 . 1\right)\left(- \overset{^}{i}\right)

= 0 . 1\left(- \overset{^}{i}\right)

\overset{\to}{τ} = \overset{\to}{M} \times \overset{\to}{B} = 0 .1 \left(- \overset{^}{i}\right) \times \left(2 \times {10}^{- 3}\right)\left(\overset{^}{j}\right)

= 2 \times {10}^{- 4}\left(- \overset{^}{k}\right)Nm

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