The current of 5 A flows in a square loop of sides 1 m is placed in air. The magnetic field at the centre of the loop is X 2 × 10 - 7 T . The value of X is _________.

Step-by-step solution

Magnetic field at the centre of the square loop is given by, B = 4 μ 0 I 4 π d sin 45 ° + sin 45 ° , where d is perpendicular distance of the centre to one of its sides. ⇒ B = 4 × μ 0 × 5 4 π × 1 2 1 2 + 1 2 = 4 × 10 - 7 × 5 × 2 × 2 = 40 2 × 10 - 7 T