A charge of 4 . 0 is moving with a velocity of 4 . 0 × 10 ^ 6 m s ^...

Given:

q = 4\muC, \overset{\to}{v} = 4 \times {10}^{6}\overset{^}{j}m{s}^{- 1} and \overset{\to}{B} = 2\overset{^}{k}T

Force acting on charged particle, $\overset{\to}{F} = q ( \overset{\to}{v} \times \overset{\to}{B} )$

= 4 \times {10}^{- 6}\left(4 \times {10}^{6}\overset{^}{j} \times 2\overset{^}{k}\right)

= 4 \times {10}^{- 6} \times 8 \times {10}^{6}\overset{^}{i}

⇒ \overset{\to}{F} = 32\overset{^}{i}N

$⇒ x = 32$