A charge of 4 . 0 μ C is moving with a velocity of 4 . 0 × 10 6 m s - 1 along the positive y -axis under a magnetic field B of strength ( 2 k ^ ) T . The force acting on the charge is x i ^ N . The value of x is ______.

Step-by-step solution

Given: q = 4 μ C , v → = 4 × 10 6 j ^ m s - 1 and B → = 2 k ^ T Force acting on charged particle, F → = q ( v → × B → ) = 4 × 10 - 6 4 × 10 6 j ^ × 2 k ^ = 4 × 10 - 6 × 8 × 10 6 i ^ ⇒ F → = 32 i ^ N ⇒ x = 32