A straight wire carrying a current of 14A is bent into a...

A straight wire carrying a current of $14A$ is bent into a semicircular arc of radius $2 . 2cm$ as shown in the figure. The magnetic field produced by the current at the centre $O$ of the arc is ____ $\times {10}^{– 4}T$

A straight wire carrying a current of 14A is bent into a semicircular arc of radius 2 . 2cm as shown in the figure. The

Correct answer

Step-by-step solution

It is given that
$i = 14AR = 2 . 2 \times {10}^{- 2}m$
The magnetic field at the centre $O$ is
$B = \dfrac{{\mu}_{0}i}{4R} = \dfrac{4\pi \times {10}^{- 7} \times 14}{4 \times 2 . 2 \times {10}^{- 2}} = 2 \times {10}^{- 4}T$

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