Two identical circular wires of radius 20 cm and carrying current 2 A are placed in perpendicular planes as shown in figure. The net magnetic field at the centre of the circular wires is ________ × 10 - 8 T . (Take π = 3 . 14 )

Step-by-step solution

The formula to calculate the magnetic field B at the centre of a current carrying circular loop is given by B =   μ 0 i 2 R       . . . ( 1 ) where, μ 0 is the permeability of free space, i is the current and R is the radius of the loop. B V ,   B H are the magnetic field due to the vertical and the horizontal loop, which by magnitude are equal. The resultant magnetic field B n e t at the centre is, then, given by B net  = B 2 + B 2 = 2 B = 2 × 4 π × 10 - 7 &#2