JEE Main20231 Feb 2023Evening ShiftPhysicsMagnetic Effects of CurrentActual
As shown in the figure, a long straight conductor with semicircular arc of radius π 10 m is carrying current I = 3 A . The magnitude of the magnetic field. at the center O of the arc is: (The permeability of the vacuum = 4 π × 10 - 7 NA - 2 )
Options
- A6   μT
- B1   μT
- C4   μT
- D3   μT
Correct answer
D. 3   μT
Step-by-step solution
The formula to calculate the magnetic field B C produced at the centre of a circular current carrying conductor is given by B C =   μ o I 4 π r θ . . . . . . . . . . . . . . . . . . . . . . . ( 1 ) where, μ 0 is the permeability of free space, I is the current through the conductor, r is the radius of the circular conductor and θ is the angle subtended by the arc at the centre. From the given figure, it is clear that the arc of the conductor makes an angle π at its centre. Substit