JEE Main20231 Feb 2023Morning ShiftPhysicsMagnetic Effects of CurrentActual
A charge particle of 2 μC accelerated by a potential difference of 100 V enters a region of uniform magnetic field of magnitude 4 mT at right angle to the direction of field. The charge particle completes semicircle of radius 3 cm inside magnetic field. The mass of the charge particle is ______ × 10 - 18 kg .
Correct answer
0
Step-by-step solution
As we know, radius of the circular path is given by, r = m v q B = 2 m K q B = 2 × m × q V q B ⇒ r 2 = 2 m V q B 2 ⇒ m = r 2 q B 2 2 V = 3 × 10 - 2 2 × 2 × 10 - 6 × 4 × 10 - 3 2 2 × 100 = 144 × 10 - 18   kg