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JEE Main 202330 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2023 · 30 January · Evening Shift · Physics · Magnetic Effects of Current

A current carrying rectangular loop PQRS is made of uniform wire....

A current carrying rectangular loop PQRSPQRS is made of uniform wire. The length PR=QS=5cmandPQ=RS=100cmPR = QS = 5cm\text{and}PQ = RS = 100cm. If ammeter current reading changes from Ito2II to 2I, the ratio of magnetic forces per unit length on the wire PQPQ due to wire RSRS in the two cases respectively (fPQI:fPQ2I)\left({f}_{PQ}^{I}: {f}_{PQ}^{2I}\right) is:

A current carrying rectangular loop PQRS is made of uniform wire. The length PR = QS = 5cmandPQ = RS = 100cm . If

Options

  1. A1:21: 2
  2. B1:41: 4
  3. C1:51: 5
  4. D1:31: 3

Correct answer

B. 1:41: 4

Step-by-step solution

Force acting per unit length between two parallel wires is given by, f=μ0I1I22\pidf = \dfrac{{\mu}_{0}{I}_{1}{I}_{2}}{2\pid}.

Clearly, f∝I1I2f ∝ {I}_{1}{I}_{2}

Therefore, fPQI:fPQ2I=I×I(2I)×(2I)=1:4{f}_{PQ}^{I}: {f}_{PQ}^{2I} = \dfrac{I \times I}{\left(2I\right) \times \left(2I\right)} = 1: 4

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