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JEE Main202330 Jan 2023Evening ShiftPhysicsMagnetic Effects of CurrentActual

A current carrying rectangular loop P Q R S is made of uniform wire. The length P R = Q S = 5 cm and P Q = R S = 100 cm . If ammeter current reading changes from I to 2 I , the ratio of magnetic forces per unit length on the wire P Q due to wire R S in the two cases respectively f P Q I : f P Q 2 I is:

Options

  1. A1 : 2
  2. B1 : 4
  3. C1 : 5
  4. D1 : 3

Correct answer

B. 1 : 4

Step-by-step solution

Force acting per unit length between two parallel wires is given by, f = μ 0 I 1 I 2 2 π d . Clearly, f ∝ I 1 I 2 Therefore, f P Q I : f P Q 2 I = I × I 2 I × 2 I = 1 : 4

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