A wire of length 314cm carrying current of 14A is bent to form a...

Length of the wire $l$ when bent becomes circumference of the loop, whose radius is given by $R = \dfrac{l}{2\pi} = \dfrac{314}{100\left(2 \times 3 . 14\right)} = \dfrac{1}{2}m$

Magnetic moment of the coil is $M = IA$

$= 14 \times \pi{R}^{2}$

$= 14 \times \left(3 . 14\right) \times \dfrac{1}{4}$

$= 10 . 99 \approx 11 . 00A - {m}^{2}$