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JEE Main 202229 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2022 · 29 June · Evening Shift · Physics · Magnetic Effects of Current

Given below are two statements : Statement I : The electric force...

Given below are two statements :
Statement II: The electric force changes the speed of the charged particle and hence changes its kinetic energy; whereas the magnetic force does not change the kinetic energy of the charged particle.
Statement IIII: The electric force accelerates the positively charged particle perpendicular to the direction of electric field. The magnetic force accelerates the moving charged particle along the direction of magnetic field.

In the light of the above statements, choose the most appropriate answer from the options given below :

Options

  1. ABoth Statement II and Statement IIII are correct.
  2. BBoth Statement II and Statement IIII are incorrect.
  3. CStatement II is correct but Statement IIII is incorrect.
  4. DStatement II is incorrect but Statement IIII is correct.

Correct answer

C. Statement II is correct but Statement IIII is incorrect.

Step-by-step solution

When a charged particle moves in an electric field, the field applies an electric force (F→=qE→)\left(\overset{\to}{F} = q\overset{\to}{E}\right) along the field, so work done by electric field is non-zero resulting in accelerated motion, thus kinetic energy changes.

When a particle moves in a uniform magnetic field, the force due to magnetic field on it is perpendicular to its velocity, as force (F→=qv→×B→)\left(\overset{\to}{F} = q\overset{\to}{v} \times \overset{\to}{B}\right).
Since the magnetic field is constant, so force is constant. So, its direction of velocity constantly changes, but magnitude of velocity remains same. Hence, kinetic energy also does not change.

Electric field accelerates the particle in the direction of field (F→=qE→=ma→)\left(\overset{\to}{F} = q\overset{\to}{E} = m\overset{\to}{a}\right)and magnetic field accelerates the particle perpendicular to the field \left(\overset{\to}{F} = q\overset{\to}{v} \times \overset{\to}{B} = m\overset{\to}{a}\right)$.

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