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JEE Main 202126 AugustMorning Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2021 · 26 August · Morning Shift · Physics · Magnetic Effects of Current

The fractional change in the magnetic field intensity at a distance...

The fractional change in the magnetic field intensity at a distance rr from centre on the axis of current carrying coil of radius aa to the magnetic field intensity at the centre of the same coil is: (Take r<ar < a)

Options

  1. A23a2r2\dfrac{2}{3}\dfrac{{a}^{2}}{{r}^{2}}
  2. B32a2r2\dfrac{3}{2}\dfrac{{a}^{2}}{{r}^{2}}
  3. C32r2a2\dfrac{3}{2}\dfrac{{r}^{2}}{{a}^{2}}
  4. D23r2a2\dfrac{2}{3}\dfrac{{r}^{2}}{{a}^{2}}

Correct answer

C. 32r2a2\dfrac{3}{2}\dfrac{{r}^{2}}{{a}^{2}}

Step-by-step solution

As we know,

Baxis=μ0iR22(R2+x2)3/2where,R=a{B}_{axis} = \dfrac{{\mu}_{0}{iR}^{2}}{2{\left({R}^{2} + {x}^{2}\right)}^{3 / 2}}\text{where}, R = a

Bcentre=μ0i2a{B}_{\text{centre}} = \dfrac{{\mu}_{0}i}{2a}

∴Baxis=μ0ia22(a2+r2)3/2∴ {B}_{\text{axis}} = \dfrac{{\mu}_{0}{ia}^{2}}{2{\left({a}^{2} + {r}^{2}\right)}^{3 / 2}}

∴∴ fractional change in magnetic field =μ0i2a−μ0ia22(a2+r2)3/2μ0i2a=1−1[1+(r2a2)]3/2= \dfrac{\dfrac{{\mu}_{0}i}{2a} - \dfrac{{\mu}_{0}i{a}^{2}}{2{\left({a}^{2} + {r}^{2}\right)}^{3 / 2}}}{\dfrac{{\mu}_{0}i}{2a}} = 1 - \dfrac{1}{{\left[1 + \left(\dfrac{{r}^{2}}{{a}^{2}}\right)\right]}^{3 / 2}}

≈1−[1−32r2a2]=32r2a2\approx 1 - \left[1 - \dfrac{3}{2}\dfrac{{r}^{2}}{{a}^{2}}\right] = \dfrac{3}{2}\dfrac{{r}^{2}}{{a}^{2}}

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