Magnitude of magnetic field (in SI units) at the centre of a hexagonal shape coil of side 10 cm , 50 turns and carrying current I (Ampere) in units of μ 0 I π is :

Step-by-step solution

The magnetic field due to the current-carrying finite length wire is given by B = μ 0 I 4 π R sin θ 1 + sin θ 2 Here for hexagonal shape coil, θ 1 = θ 2 = 30 ° . So, the net magnetic field at the centre will be B = 50 × 6 × μ 0 i 4 π 10 100 cos   30 ° sin   30 ° + sin   30 ° B = 2 × 75 × 10 μ 0 i 3 π 1 2 + 1 2 B = 1500 3 μ 0 i π       = 500 3 μ 0 i π