Proton with kinetic energy of 1 M e V moves from south to north. It gets an acceleration of 10 12 m / s 2 by an applied magnetic field (west to east). The value of magnetic field: (Rest mass of proton is 1.6 × 10 - 27 k g )

Step-by-step solution

∴ K . E . = 1.6 × 10 - 13 = 1 2 × 1.6 × 10 - 27 v 2 v = 2 × 10 7 m / s ∴ B q v = m a B = 1.6 × 10 - 27 × 10 12 1.6 × 10 - 19 × 2 × 10 7 = 0.71 × 10 - 3 T So, B = 0 . 71   m T