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JEE Main20207 Jan 2020Evening ShiftPhysicsMagnetic Effects of CurrentActual

The electric field of a plane electromagnetic wave is given by E → = E 0 i ^ + j ^ 2 cos ⁡ k z + ω t . At t = 0 , a positively charged particle is at the point x , y , z = 0 , 0 , π k . If its instantaneous velocity at t = 0 is v 0 k ^ , the force acting on it due to the wave is:

Options

  1. Aparallel to i ^ + j ^ 2
  2. Bzero
  3. Cantiparallel to i ^ + j ^ 2
  4. Dparallel to k ^

Correct answer

C. antiparallel to i ^ + j ^ 2

Step-by-step solution

Force due to electric field is in direction – i ^ + j ^ 2 E 0 Force due to magnetic filed is in direction q v → × B → and v → | | k ^ ∴ it is parallel to E → ∴ net force is antiparallel to i ^ + j ^ 2 .

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