JEE Main20198 Apr 2019Evening ShiftPhysicsMagnetic Effects of CurrentActual
Two magnetic dipoles X and Y are placed at a separation d , with their axes perpendicular to each other. The dipole moment of Y is twice that of X . A particle of charge q is passing through their mid-point P , at angle θ = 45 o with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant? ( d is much larger than the dimension of the dipole)
Options
- A0
- B2 μ 0 4 π M d 2 3 × q v
- Cμ 0 4 π M d 2 3 × q v
- Dμ 0 4 π 2 M d 2 3 × q v
Correct answer
A. 0
Step-by-step solution
B X = 2 μ 0 4 π M d / 2 along x -axis B Y = μ 0 4 π 2 M d / 2 along y -axis B X = B Y Hence B n e t will be at 45 o from x -axis. Now, velocity and magnetic field are in same direction. Hence no force will act on the particle.