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JEE Main201911 Jan 2019Evening ShiftPhysicsMagnetic Effects of CurrentActual

A particle of mass m and charge q is in an electric and magnetic field given by E =2 i +3 j ; B =4 j +6 k The charged particle is shifted from the origin to the point P (x=1 ; y=1) along a straight path. The magnitude of the total work done is :

Options

  1. A(0.35) q
  2. B5 q
  3. C(2.5) q
  4. D(0.15) q

Correct answer

B. 5 q

Step-by-step solution

Resultant force on the charged particle array l = F _ net = q E + q ( V B ) =(2 q i +3 q j )+ q ( v B ) array Also q ( V B )=0 So, required work done aligned W &= F _ net S =(2 q i +3 q j ) ( i + j ) &=2 q +3 q &=5 q aligned

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