JEE Main2016PhysicsMagnetic Effects of CurrentActual
A conducting metal circular-wire-loop of radius r is placed perpendicular to a magnetic field which varies with time as B = B 0 e - t τ , where B 0 and τ are constants at time t = 0 . If the resistance of the loop is R , then the heat generated in the loop after a long time t → ∞ is
Options
- Aπ 2 r 4 B 0 4 2 τ R
- Bπ 2 r 4 B 0 2 2 τ R
- Cπ 2 r 4 B 0 2 R τ
- Dπ 2 r 4 B 0 2 τ R
Correct answer
B. π 2 r 4 B 0 2 2 τ R
Step-by-step solution
Here, B = B 0 e - t τ Area of the circular loop, A = π r 2 Flux linked with the loop at any time   t , ϕ = B A = π r 2 B 0 e - t τ   Emf induced in the loop, ε = - d ϕ d t = π r 2 B 0 1 τ e - t τ Net heat generated in the loop ∫ 0 ∞ ε 2 R d t = π 2 r 4 B 0 2 τ 2 R ∫ 0 ∞ e - 2 t τ d t = π 2 r 4 B 0 2 τ 2 R × 1 - 2 τ × e - 2 t τ 0 ∞ = - π 2 r 4 B 0 2 2 τ 2 R × `