JEE Main2013PhysicsMagnetic Effects of CurrentActual
A particle of charge 16 10⁻¹⁶ C moving with velocity 10 ~ms ⁻¹ along x -axis enters a region where magnetic field of induction B is along the y -axis and an electric field of magnitude 10^4 Vm ⁻¹ is along the negative z -axis. If the charged particle continues moving along x -axis, the magnitude of B is :
Options
- A16 10^3 ~Wb ~m ⁻²
- B2 10^3 ~Wb ~m ⁻²
- C1 10^3 ~Wb ~m ⁻²
- D4 10^3 ~Wb ~m ⁻²
Correct answer
C. 1 10^3 ~Wb ~m ⁻²
Step-by-step solution
Since particle is moving undeflected So, q_E=q v B B= E V = 10^4 10 =10^3 wb / m ^2