The magnetic field due to a current carrying circular loop of radius 3 ~cm at a point on the axis at a distance of 4 ~cm from the centre is 54 T . What will be its value at the centre of the Loop?

Step-by-step solution

Using formula B= ₀^ II 2 (R^2+X^2 )^ 3 / 2 , we get 54= ₀ i(3)^2 2 [(3)^2+(4)^2 ]^ 3 / 2 At the centre of the coil, X=0 and B= ₀ i 2(3) Using equation (i) B= 54 5^3 (3)^2 3 B=250 T .