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JEE Main2003PhysicsMagnetic Effects of CurrentActual

A particle of charge -16 10⁻¹⁸ coulomb moving with velocity 10 ~ms ⁻¹ along the x -axis enters a region where a magnetic field of induction B is along the y -axis, and an electric field of magnitude 10^4 ~V / m is along the negative z-axis. If the charged particle continues moving along the x -axis, the magnitude of B is

Options

  1. A10^3 ~Wb / m ^2
  2. B10^5 ~Wb / m ^2
  3. C10¹⁶ ~Wb / m ^2
  4. D10⁻³ ~Wb / m ^2

Correct answer

A. 10^3 ~Wb / m ^2

Step-by-step solution

Since there is no deviation in the path of the charged particle, so net force due to presence of electric and magnetic field must be zero vB = qE B = E V = 10^4 10 =10^3 ~Wb / m ^2

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