JEE Main202227 Jun 2022Evening ShiftPhysicsMagnetic Properties of MatterActual
A metallic rod of length 20 cm is placed in North-South direction and is moved at a constant speed of 20 m s - 1 towards East. The horizontal component of the Earth's magnetic field at that place is 4 × 10 - 3 T and the angle of dip is 45 ° . The emf induced in the rod is _____ mV .
Correct answer
0
Step-by-step solution
Emf produced is ε = B V L ⊥ v ⊥ We know B V B H = tan 45 ° , so B V = 4 × 10 - 3   T Then, ε = 4 × 10 - 3 × 20 × 10 - 2 × 20 = 16   mV