If the percentage errors in measuring the length and the diameter of a wire are 0 . 1 % each. The percentage error in measuring its resistance will be:

Step-by-step solution

Resistance of the wire in terms of the diameter can be written as, R = ρ L π d 2 4 Hence, percentage error relation will be, ∆ R R × 100 = ∆ L L × 100 + 2 ∆ d d × 100 Given: ∆ L L = 0 . 1 % and ∆ d d = 0 . 1 % Therefore, ∆ R R = 0 . 3 %