JEE Main 202311 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 11 April
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Mathematics in Physics
JEE Main 2023 · 11 April · Evening Shift · Physics · Mathematics in Physics
When vector → A = 2 ^ i + 3 ^ j + 2 ^ k is subtracted from vector →...
When vector \overset{\to}{A} = 2\overset{^}{i} + 3\overset{^}{j} + 2\overset{^}{k} is subtracted from vector , it gives a vector equal to 2\overset{^}{j}. Then the magnitude of vector will be:
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
It is given that \overset{\to}{A} = 2\overset{^}{i} + 3\overset{^}{j} + 2\overset{^}{k}.
By the given condition,
\overset{\to}{B} - ( 2\overset{^}{i} + 3\overset{^}{j} + 2\overset{^}{k} ) = 2\overset{^}{j}
⇒ \overset{\to}{B} = 2\overset{^}{i} + 5\overset{^}{j} + 2\overset{^}{k}
The magnitude is given by the formula,\left|\overset{\to}{B}\right| = \sqrt{{B}^{2}x + {B}^{2}y + {B}^{2}z}⇒ | \overset{\to}{B} | = \sqrt{4 + 25 + 4} = \sqrt{33}