A silver wire has a mass (0 . 6 ± 0 . 006)g , radius (0 . 5 ± 0 ....

Volume of the wire is $V = \pi{r}^{2}l$.

Density of the wire is $ρ = \dfrac{m}{\pi{r}^{2}l}$

Relative error in measurement of density

$⇒ \dfrac{\Deltaρ}{ρ} = \dfrac{\Deltam}{m} + 2 \times \dfrac{\Deltar}{r} + \dfrac{\Deltal}{l}$

$= \dfrac{0 . 006}{0 . 6} + 2 \times \dfrac{0 . 005}{0 . 5} + \dfrac{0 . 04}{4}$

$= 0 . 01 + 0 . 02 + 0 . 01 = 0 . 04$

$∴$ Percentage error in $ρ = 0 . 04 \times 100 = 4$