If the length of the pendulum in pendulum clock increases by 0 . 1 % , then the error in time per day is:

Step-by-step solution

T = 2 π l g T ∝ l 1 2 Δ T T = 1 2 Δ l l Δ T 24 × 3600 = 1 2 × 0 . 1 100 Δ T = 1 2 × 0 . 1 100 × 24 × 3600 Δ T = 43 . 2   s