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JEE Main202118 Mar 2021Morning ShiftPhysicsMathematics in PhysicsActual

The time period of a simple pendulum is given by T = 2 π l g . The measured value of the length of the pendulum is 10 cm known to a 1 mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of g using this pendulum is x . The value of x to the nearest integer is:-

Options

  1. A2 %
  2. B3 %
  3. C5 %
  4. D4 %

Correct answer

B. 3 %

Step-by-step solution

g = 4 π 2 l T 2 Δ g g = Δ l l + 2 Δ T T = 0 . 1 10 + 2 1 200 0 . 5 Δ g g = 1 100 + 1 50 Δ g g × 100 = 3 %

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